Mathematics
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OpenStudy (yacoub1993):
Graph the function by making a table of coordinates.
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OpenStudy (yacoub1993):
\[f(x) =(\frac{ 3 }{ 4 }) x\]
OpenStudy (yacoub1993):
OpenStudy (isaiah.feynman):
The shapes of the graphs looks like those of an exponential function. But your function looks linear.
OpenStudy (anonymous):
Exactly
OpenStudy (yacoub1993):
thats the way i was asked
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OpenStudy (anonymous):
Maybe you wrote the function wrong?
OpenStudy (yacoub1993):
f(x)=(3/4)x
OpenStudy (anonymous):
The "x" isn't an exponent?
OpenStudy (yacoub1993):
i dont know
OpenStudy (isaiah.feynman):
Wow. Just wow.
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OpenStudy (isaiah.feynman):
Twisted math.
OpenStudy (anonymous):
Ikr?
OpenStudy (anonymous):
If the x was an exponent then the answer would be A...
OpenStudy (yacoub1993):
what do u mean by an exponent
OpenStudy (anonymous):
You don't know what an exponent is?
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OpenStudy (anonymous):
Look:
\[5^{2}\]
The "2" is an exponent
OpenStudy (anonymous):
Is the "x" like that?
OpenStudy (yacoub1993):
ohhh
OpenStudy (yacoub1993):
can it be called exponent if it is like thatv\[5_{x}\]
OpenStudy (yacoub1993):
because when i took a closer look at the question it look like the x is smaller that the x that is beside f
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OpenStudy (anonymous):
Does your function look like this?
\[f(x) = \left(\begin{matrix}3 \\ 4\end{matrix}\right)^{x}\]
OpenStudy (anonymous):
Yes it can.
OpenStudy (yacoub1993):
if i take a closer look it looks like this \[f (x) =(\frac{ 3 }{ 4 })_{x}\]
OpenStudy (yacoub1993):
because the last x is smaller in size
OpenStudy (anonymous):
Well it's the same thing
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OpenStudy (anonymous):
So A is your answer :)
OpenStudy (anonymous):
Just remember if graphs have curves that means there is an exponent involved and if you don't see an exponent re-check your function :)
OpenStudy (yacoub1993):
ohh my fault sorry.... i thought there is no difference between a normal x
OpenStudy (anonymous):
Okay, it's fine.
OpenStudy (yacoub1993):
i will tag u if i have question ok....
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OpenStudy (anonymous):
Oki-Dok