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undeadknight26 (undeadknight26):
hi. what may the question be?
OpenStudy (anonymous):
Find the missing side length.
a. 12 in
b. 15 in
c. 17 in
d. 21 in
undeadknight26 (undeadknight26):
they ever gave u a perimeter or anything?
undeadknight26 (undeadknight26):
from this point it can be anything..
OpenStudy (anonymous):
Nope. thats all the question was. thats why i dont understand.
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OpenStudy (anonymous):
Use the Pythagorean equation
OpenStudy (anonymous):
It's a right triangle, therefore we can use that equation to find the length of the hypotenuse.
The equation is as so:
\[c^2 = a^2 + b^2\]can you solve for "c" from here?
OpenStudy (anonymous):
|dw:1384367566468:dw|
OpenStudy (anonymous):
I got 18+144
OpenStudy (anonymous):
9^2 = 81 not 18
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OpenStudy (anonymous):
Oh yeah. Oops.
OpenStudy (anonymous):
so you found out that \[c^2 = 81+144\]how would you find "c"?
OpenStudy (anonymous):
225
OpenStudy (anonymous):
okay that still leaves \[c^2= 225\]we need to find the singular value of "c" not the c^2, what would you do?
OpenStudy (anonymous):
divide by 2?
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OpenStudy (anonymous):
No. When you see a letter or number that has an exponent of "2" we say that it is "Squared" right?
so c^2 or \[c^2\] we say it's "c squared", or in expansion it looks like this \[c \times c\] how do we "unsquare" it
OpenStudy (anonymous):
Raise it to a half power? i dont really know.
OpenStudy (anonymous):
We square root it. It looks as so
\[\sqrt{c ^{2}}= \sqrt{225}\]You seen that before right? Now, what is your answer for singular "c"