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Given f(x) = 3x-1 over 2, solve for f-1(4)
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\[\frac{ 3x-1 }{ 2 }\]
hmm, is that f-1(4) this; \[f _{1}(4)\] ?
its f\[f^{-7}\]
i mean one. whoops
Ok, the idea here is that when you apply the inverse function to the original function, you get back the input variable. i.e. \[f ^{-1}(f(x)) = x\] So setup the inverse f^(-1) to undo all the stuff that f(x) does. i.e. since f(x) multiplies x by 3 and divides by 2, you are going to multiply x by 2 and divide by 3. Also, add +1 to negate the -1 of f(x) \[f ^{-1}(x) = ((2x) \div 3) + 1 \] You can do the rest yourself.
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