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Mathematics 12 Online
OpenStudy (anonymous):

You are building a right-angled triangular flower garden along a stream as shown in the figure. The fencing of the left border costs $8 per foot, while the fencing of the lower border costs $2 per foot. (No fencing is required along the river.) You want to spend $320 and enclose as much area as possible. What are the dimensions of your garden, and what area does it enclose? [The area of a right-triangle is given by A = xy/2.] left border = ?? bottom border =?? garden area = ??

OpenStudy (anonymous):

This is the figure

OpenStudy (ranga):

|dw:1384381212786:dw| Left border cost = 8y Bottom border cost = 2x Total cost = 2x + 8y = 320 ----- (1) Area A = 1/2xy --------------- (2) Find x from (1) and substitute in (2) To maximize the area, find the derivative dA/dy, set it to 0 and solve for y. Then find x and the area A.

OpenStudy (anonymous):

i got x=160-4y Is that right?

OpenStudy (ranga):

yes.

OpenStudy (anonymous):

So when I plug it into the area, do I have to distribute the y?

OpenStudy (ranga):

yes.

OpenStudy (anonymous):

so i get 1/(2)(160y-4y^2) Then I distribute the 2?

OpenStudy (ranga):

distribute the half (1/2)

OpenStudy (anonymous):

I got 80y-2y^2

OpenStudy (ranga):

Yes, A = 80y-2y^2 Find dA/dy and set it to 0 and solve for y.

OpenStudy (anonymous):

So find the derivative of 80y-2y^2 ?

OpenStudy (ranga):

Yes. To find the minimum/maximum we have to find the critical point. That is done by taking the derivative and setting it to 0.

OpenStudy (anonymous):

Ok, so y = 20

OpenStudy (ranga):

Yes. Find x and A.

OpenStudy (anonymous):

x= 80

OpenStudy (ranga):

yes. A = ?

OpenStudy (anonymous):

A = 800 ?

OpenStudy (ranga):

That is it.

OpenStudy (anonymous):

Yay! Thank you :)

OpenStudy (ranga):

you are welcome.

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