Question

Find the slope-intercept form of an equation of the line perpendicular to the graph of x-3y=5 and passing through (0,6).

I had y=3x+6 but it's not a choice.

Answer 1

first find the slope of the perpendicular line, do you know how to do this?

Answer 2

I think this example might help.
http://openstudy.com/study#/updates/52697f82e4b040e33d2f88e7

Answer 3

\[Y=\frac{ 1 }{ 3 }X \frac{ 5 }{ 3 }\]

Answer 4

\[Y=\frac{ 1 }{ 3 }X+\frac{ 5 }{ 3 }\]

Answer 5

So, it should be y = -3x+6 because you have to do the multiplicative inverse?

Answer 6

no

Answer 7

My choices are;
A. y = 1/3x - 2
B. y = -3x + 6
C. y = 1/3x + 2
D. y = 3x - 6

Answer 8

if you take your equation \[x-3y=5\] then all you need to do with it is solve for Y

Answer 9

My bad it is y= 1/3x-3/5 in slope intercept form

Answer 10

So we know that it is going to be
y=-3x+b

since any perpendicular slope, for example for slope m, is -1/m.

now, plug in (0,6) into y=-3x+b to find the missing y-intercept
6=-3(0)+b
b=6

so it is going to be
y=-3x+6

Answer 11

Thank you. :D

Answer 12

Anytime