Question

someone check my work. (three-branch parallel network)

Answer 1

A 2.0-ohm resistor is connected in series with a 20.0-V battery and a three-branch parallel network with branches whose resistances are 8.0 ohms each. Ignoring the battery's internal resistance, what is the current in the battery? Show your work.

Answer 2

I = V / R
total resistance = 2 ohm + the total resistance of the 3 parallel resistances

1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/8 + 1/8 + 1/8 = 3/8
R = 2.6667

So total Resistance of the circuit = 2.7 + 2.0 = 4.7

I = voltage /Reistance
20/4.7 = 4.25 A

Answer 3

yes that should be correct

Answer 4

The answer rounded to 3 decimal places is 4.286 A