help.! graphing. :(
there's the graph...
okay since it only hits one value and the y is continuous you're equation si going to start vvith x +
x=
what exactly do you need help with? LOL
|dw:1384410013794:dw| if it's vertical line the equation is x=the number the line passes through if the line is horizontal the line is y=the number it passes through
then you're going to find the x that it is continuously on vvhat x value does each point on that graph match.
your line therefore passes along the x-axis
ermmmmm
your slope is undefined that is the key to your problem
because the line is not steep it's straight
note since this is all said and done and there is no slope it is simply x=3
thats the equation?
NO... WHAT IS YOUR QUESTION about the graph? LOL
vvhat is the equation of the graph
^
there's no slope because the line is steep, and if there's no b or y-intercept because the line doesn't touch the y-axis
so the equation is x = 3?
so simply put it x=3 no slope and no y-intercept
okay thanks .!
of course friend.
there's no slope because the line is not steep, and there's no b or y-intercept because the line doesn't touch the y-axis
i miss typed lol
don't believe both of them because they are giving you the answer they key is that your slope is undefined rise/run or change in y over change in x your run would be zero for it to be undefined your line can touch the y-axis at every point possible for x=0
so they're wrong?
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