Question

solve y-2x=8 2y+2x=40

Answer 1

Is this all one question?

Answer 2

if y-2x=8 is a seperate question it would be
y = 2x + 8

Answer 3

@undeadknight26 Can you help me?

Answer 4

The domain of the following relation: R: {(3, -2), (1, 2), (-1, -4), (-1, 2)} is

{-1, 1, 3}

{-1, -1, 1, 3}

{-4, -2, 2, 2}

{-4, -2, 2}

Answer 5

-1 1 3. first one...remember the domain is the x and when you are listening them you do not double list.

Answer 6

The range of the following relation: R: {(3, -2), (1, 2), (-1, -4), (-1, 2)} is

{-1, 1, 3}

{-1, -1, 1, 3}

{-4, -2, 2, 2}

{-4, -2, 2}

Answer 7

How about this one? @undeadknight26

Answer 8

YOu try this one i said that to domain is the first letter than what is the range?

Answer 9

x is the first letter

Answer 10

yes as i said before the x and the domain is the same.

Answer 11

Is it the second one?

Answer 12

please start up another question if you have more questions or email me.

Answer 13

it just says solve using subsitution method y-2x=8
2y+2x=40

Answer 14

then they are separate questions.

Answer 15

so how do i solve it

Answer 16

You are solving for y right?

Answer 17

yes

Answer 18

0037109 i cannot email to you because it is not a valid username...please start your own question.

Answer 19

So we can put it into:
y = 2x + 8
/2 /2
y = (x + 8)
i believe this is how you answer it.

Answer 20

Are we still solving for y for the second one?

Answer 21

yes

Answer 22

well then i am assuming:
2y = 2x - 40
/2 /2
2y = x - 20
/2 /2
y = x - 10?
let me double check.

Answer 23

No apparently the answer is y = 20 -x

Answer 24

I have no idea how to do that srry lol...unless
2y = 2x - 40
/2 /2 /2
y = x - 20...

Answer 25

I hope i helped.