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Chemistry 18 Online
OpenStudy (anonymous):

A 2.62g sample of a substance suspected of being pure gold is warmed to 72.3∘C and submerged into 15.6g of water initially at 24.8∘C. The final temperature of the mixture is 26.0∘C. What is the heat capacity of the unknown substance?

OpenStudy (anonymous):

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OpenStudy (anonymous):

Use the equation: heat = mass * specific heat of water * change in temperature

OpenStudy (anonymous):

So, Heat capacity (J) = (2.62)*(4.18)*(26.0 - 24.8)

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