Question

I have a very challenging question

Answer 1

i hope we dont have to guess what it is ....

Answer 2

Top Secret man....

Answer 3

\[\color{white}{top~secret~!!}\]

Answer 4

thats not all that challenging .. what else you got?

Answer 5

for me it is

Answer 6

Would this be synthetic division? Or just simplification?

Answer 7

what are you trying to do with it?

Answer 8

Simplify

Answer 9

assume 2x-5 is a factor that can cancel

(2x-5)(ax+b) = 4x^2 - 20x + 25

Answer 10

expand the left side and compare term to term

Answer 11

lost

Answer 12

do you know how to foil?

Answer 13

yes

Answer 14

then foil ...

(2x-5)(ax+b)

Answer 15

2ax^2+2xb-5ax-5b

Answer 16

nice ..

now lets make it look like x^2, x, ... by combining like parts

2ax^2+ (2b-5a) x - 5b

this HAS to be equal, term for term to the top of your setup

4 x^2 - 20 x + 25
2ax^2+ (2b-5a) x - 5b


2a = 4

2b-5a = -20

-5b = 25

Answer 17

\[\frac{\cancel{(2x-5)}(ax+b)}{\cancel{(2x-5)}}=ax+b\]