Question

A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
seconds is given by the function h(t) = –16t² + 32t + 6. What is the ball’s maximum height? How long does it
take the ball to reach its maximum height? Round to the nearest hundredth, if necessary. (1 point)
Reaches a maximum height of 22 feet after 1.00 second.
Reaches a maximum height of 22 feet after 2.00 seconds.
Reaches a maximum height of 44 feet after 2.17 seconds.
Reaches a maximum height of 11 feet after 2.17 seconds.

Answer 1

to find the 'maximum height' we will need to take the derivative of
h(t) = –16t² + 32t + 6
then set it equal to zero,
then solve for t. this t will be the time at which the ball reaches it's maximum height.

Answer 2

once we have the time for when the ball is at it's maxiumum height, we can plug it into the original equation given to us to find the height that the ball is at.
h(t) = –16t² + 32t + 6

Answer 3

So Do You Know What T Is ?

Answer 4

Me? no, i'm not going to solve it for you.

Answer 5

lol okay thanks bye :)

Answer 6

Yes yes, the 2nd and 3rd rules of OS:
Give Help, Not Answers - I will encourage and guide those needing help, and not just give them an answer
Thank Others for Their Help - I will thank people for taking the time and effort to help me

Both done. The problem is set up, and all SSmiles has to do is finish it, so SSmiles thanked DemolisionWolf. All good.

Answer 7

Boy Bye @e.mccormick

Answer 8

SSmiles, if there is some part of what DemolisionWolf said that you do not understand, all you have to do is ask about that.