Find the principal Argument for z= i/(-2-2i)
I haven't done math in a while, I know how to do the hard parts, but I can't remember if I can change i/(-2-2i) = (i/-2) - (i/2i). Sad, I know
we will even each other out, I don't know how to do Arugment stuff but i/(-2-2i) = (i/-2) - (i/2i) isn't alowed, you can only separte them like this if it was flipped upside down.
that's what i thought! Thanks for the help! basically I just need to break this up into a real and an imaginary part and I can't figure it out for the life of me.
If I invert the entire equation can I then change the stuff around and invert it again to get back?
....stinking algebra
lol
so the idea is to separate the complex from the real?
yep. I need a real part and an imaginary part. Basically I need to consolidate my i terms
here is the best I got.. |dw:1384475249351:dw|
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