The quarterback on a football team completes 60% of his passes. He attempts three passes (assumed to be independent) in a given quarter. a. What is the probability that he will complete all three? b. What is the probability that he will complete at less than 3 passes?
all three means \(.6\times .6\times .6=.6^3\)
i don't understand that
less than 3 means not three, once you have computed \[.6^3\] the probability of less than 3 is \[1-.6^3\]
.216
all three: makes the first \(60\%=.6\) chance of that AND makes the second, another \(.6\) AND makes the third \(.6\) again since all three have to happen, and since the events are assumed to be independent, you multiply them to get your probability \[.6^3\]
@satellite73 gots it :)
So .6 3 power is the answer
for the first one, yes \[.6^3\]
mhm :)
How do you make to the third power on the keyboard Victoria
So what is the second answer
to make the cube symbol hold down the ALT key then type in ³ and there it is
or just X^3 It all means the same
I am sorry I have a macbook pro. I don't have that button my computer.
so .6³ = .216
Yeah you're right. Can you copy and paste the ³
just .6^3 if you cant. we all get it
alright
As far as part b - is that asking if the quarterback will complete less than 3 passes?
That's what I see.
Then I guess p = 1 -.216 = 0.784
Thanks guys and girls
u r welcome
Mhm no problem :)
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