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Calculus1
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d/dx (xe^(lnx^2)) =?
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since e^x and lnZ(x) are inverse operations, it is true that:\[\ln(e^x) = x\] and\[e^{\ln(x)} = x\] using same logic:\[e^{\ln(x^2)} = x^2\] we aer now looking for d/dx (x*x^2) = d/dx x^3 i think you can handle it now ^_^
x^3?
x*e^(lnx^2) = x^3 so you have to derive x^3
i understand now :)
3x^2 thanks :)
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