A company with loud machinery needs to cut its sound intensity to 37% of its original level. By how many decibels would the loudness be reduced? Use the formula

L = 10 Log I over I 0

Question

A company with loud machinery needs to cut its sound intensity to 37% of its original level. By how many decibels would the loudness be reduced? Use the formula
 
L = 10 Log I over I 0

anonymous · Answer

my guess is to set 
$$10\log(\frac{I}{I_0})=.37$$and solve for $I$

anonymous · Answer

i think it is best to ignore the $I_0$ and solve via 
$$\log(I)=.037$$
$$I=10^{.037}$$

anonymous · Answer

but i could be wrong

anonymous · Answer

@SolomonZelman sorry i was in jrotc and i had a teacher help me and and we came up with the equation L = 10 Log . 37 , close to yours. so now my question is do i add log to the equation when i plug it into my claculator or no ?

anonymous · Answer

* i was in jrotc . I had a teacher help me. sorry that was grammatically incorrect

solomonzelman · Answer

What is your formula that you are dealing with, can you type it in equations, so that I know what exactly you are talking about?