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Geometry 18 Online
OpenStudy (anonymous):

Find the range for the measurement of the third side of a triangle, x, given the measures of the two sides: 5m and 11m. A. 6m < x < 16m B. 5m < x < 11m C. 6m < x < 16m D. 7m < x < 17m

OpenStudy (jdoe0001):

try using this triangle -> http://www.mathsisfun.com/geometry/triangles-interactive.html grab point C and make it 107 degrees, notice the legs AB and AC are about a ratio of 5 and 11 respectively then move the point C to make the angle A bigger or smaller

OpenStudy (jdoe0001):

so as angle A shrinks or expands..... how small do you think you can make the side BC? how big do you think BC can get?

OpenStudy (jdoe0001):

well... maybe 107 degrees may not suffice... anyhow the idea is to use C to make the legs AB and AC 5 and 11, so you can check

OpenStudy (anonymous):

is it c?

OpenStudy (jdoe0001):

hmm what makes you think is C?

OpenStudy (jdoe0001):

|dw:1384541331718:dw|

OpenStudy (jdoe0001):

see how far the angle can shrink? or expand? how big will the 3rd leg be when that happens? how small can it get? how big can it get?

OpenStudy (anonymous):

3 and 16

OpenStudy (anonymous):

im lost lol

OpenStudy (jdoe0001):

|dw:1384541566898:dw|

OpenStudy (jdoe0001):

now if both lines touch each other, that is, we shrink the angle between them to 0, then you won't have a triangle, just 3 flat lines so the 3rd leg will have to be \(\bf \ne 0;\ thus \ > 0\) now if both lines expand fully and lay flat on their back, then you won't have a triangle either, just again, 3 flat lines so the 3rd leg will have to be \(\bf \ne 16\ thus \ < 16\)

OpenStudy (jdoe0001):

hmmm I mean.... \(\bf \ne 6; \ thus \ > 6\)

OpenStudy (jdoe0001):

when the 2 lines have an angle of 0 between them, the 3rd leg will be the slack of 11-5, so 6

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