given a triangle with a=16, A=29 degrees, and B= 28 degreess, what is the lenth of c?
a. 25.4
b. 22.4
c. 24.4
d. 23.4

Question

given a triangle with a=16, A=29 degrees, and B= 28 degreess, what is the lenth of c?
a. 25.4
b. 22.4
c. 24.4
d. 23.4

jdoe0001 · Answer

if $\bf \measuredangle A=16^o\quad \measuredangle B=28^o$   what is the length of $\bf \measuredangle C\quad ?$

jdoe0001 · Answer

when you find $\bf \measuredangle C$, use the Law of Sines to get side "c"

anonymous · Answer

136

jdoe0001 · Answer

hmmm wait... I... shoot... a =16... A = 29  =(

jdoe0001 · Answer

anyhow your sum was correct either   $\bf \measuredangle A=29^o\quad \measuredangle B=28^o \quad \measuredangle C = 123^o$

jdoe0001 · Answer

using the Law of Sines $\bf \cfrac{sin(123^o)}{c}=\cfrac{sin(29^o)}{16}$

anonymous · Answer

is it B?

jdoe0001 · Answer

... what did you get?

anonymous · Answer

honestly idk

anonymous · Answer

can you show me how to do it?!

jdoe0001 · Answer

have  you covered the Law of Sines yet?

anonymous · Answer

ya but i dont get it

jdoe0001 · Answer

well... is very straighforward from $\bf \cfrac{sin(123^o)}{c}=\cfrac{sin(29^o)}{16}$   just solve for "c"

jdoe0001 · Answer