Question

A manufacturer claims that fewer than 6% of its fax machines are defective. In a random sample of 97 such fax machines, 5% are defective. Find the P-value for a test of the manufacturers claim. HELP!!

Answer 1

Given A manufacturer claims that fewer than 6% of its fax machines are defective. In a random sample of 97 such fax machines, 5% are defective
the z-value of that sample proportion:
=>z(0.05) = (0.05-0.06)/sqrt[0.05*0.95/97]
=>z= -0.4520
again P-value for a test of the manufacturer's claim.
=>p-value = P(z < -0.4520) = tcdf(-100,-0.4520 when df = 96)
=>p= 0.3262

Know more about Sample Mean http://goo.gl/Gi2fhl