A manufacturer claims that fewer than 6% of its fax machines are defective. In a random sample of 97 such fax machines, 5% are defective. Find the P-value for a test of the manufacturers claim. HELP!!

Question

A manufacturer claims that fewer than 6% of its fax machines are defective.  In a random sample of 97 such fax machines, 5% are defective. Find the P-value for a test of the manufacturers claim.  HELP!!

jmark · Answer

Given A manufacturer claims that fewer than 6% of its fax machines are defective. In a random sample of 97 such fax machines, 5% are defective the z-value of that sample proportion: =>z(0.05) = (0.05-0.06)/sqrt[0.05*0.95/97] =>z= -0.4520 again P-value for a test of the manufacturer's claim. =>p-value = P(z < -0.4520) = tcdf(-100,-0.4520 when df = 96) =>p= 0.3262 Know more about Sample Mean http://goo.gl/Gi2fhl