Question

Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. a = 7, b = 7, c = 5

A. A = 70°, B = 70°, C = 40°
B. A = 69°, B = 69°, C = 42°
C. A = 42°, B = 69°, C = 69°
D. A = 69°, B = 42°, C = 69°

Answer 1

I am sure it isnt D because i got wrong

Answer 2

The height or altitude of the triangle =
hgt² = 7² - 2.5²
hgt² = 49 -6.25
hgt² = 42.75
hgt = 6.538

angle A = arc tan (6.538 / 2.5)
angle A = arc tan (2.6152)
angle A = 69.0741
angle A = 69°

angle B = angle A = 69°

angle C = 180 -69 -69
angle C = 42°

and there you have it !!!

Answer 3

thnxs @wolf1728

Answer 4

This is the complete diagram of the triangle.

Answer 5

u r welcome yacoub

Answer 6

i was confused with which law to solve for the first and second angles

Answer 7

I know that people here will mention about law of sines, law of cosines and so on.
I think it is much easier to remember the trigonometric functions (sine = opp/hyp) and you can figure out everything else yourself.

Answer 8

ohh ok
i have another question which have no idea how to solve... Can u help me with it?

Answer 9

okay go ahead

Answer 10

Find the quotient z1/z2 of the complex numbers. Leave answer in polar form.
\[z1 = \frac{ 1 }{ 8 }(\cos \frac{ 2\pi }{ 3 }=i \sin \frac{ 2\pi }{ 3 })\]
\[z2= \frac{ 1 }{ 3 }(\cos \frac{ \pi }{ 4 }+i \sin \frac{ \pi }{ 4 })\]

Answer 11

@wolf1728 sory for late reply.....my internet conection went down