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Mathematics 20 Online
OpenStudy (anonymous):

If you were asked to convert 3.5 moles of aluminum to grams, which of the following should you use for the conversion? Select one: a. fraction: 6.022 times 10 superscript 23 atoms Al over one mol Al atoms b. fraction: 26.981 g Al over one mol Al c. fraction: 13.0 g Al over one mol Al d. fraction: 6.022 times 10 superscript 23 atoms Al over 26.981 mol Al atoms

OpenStudy (anonymous):

B. \[3.5 mols Al \left( \frac{ 26.982g Al }{ 1 mol Al } \right)= 94.437g Al\]

OpenStudy (anonymous):

are you sure about this

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

100%

OpenStudy (anonymous):

B. says 26.981not 26.982 in your answer

OpenStudy (anonymous):

A. would be used if you were given the number of atoms. C. is using the wrong molar mass for Al. D. Wouldn't result in grams.

OpenStudy (anonymous):

You can get different answers based on different periodic tables. I used a periodic table that has a slight different molar mass. Your question used 26.981, but my table has 26.982 as the molar mass.

OpenStudy (anonymous):

so its still the same answer

OpenStudy (anonymous):

Yeah, it's still the same answer.

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