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what is the derivative of s(t)=-0.001t(t+35)(t-35)
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It might be easier to multiply out your expression (t+35)(t-35) will give a difference of squares. then multiply by t (leave the -0.001 out of all this until the very end)
oki @phi so I got t^2-35t+35t-1125 now what
first notice -35t+35t is 0 second 35*35= 1225 now (ignoring the -0.001) you have t(t^2- 1225) distribute the t \[ t^3 -1225t\]
now take the derivative term by term then multiply everything by -0.001
is it -0.003t^2-1.225
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@phi
1.225 shouldn't be negative, otherwise it's correct. \[s'(t)=-0.003x^2+1.225\]
thankyou sooooo much
You're welcome. It seems you forgot to change the sign when you distributed -0.001 earlier.
woops
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