Question

Rewrite sin(2sin^-1x)

Answer 1

sin(2sin^-1x) sin(2sin^-1x) <--- REwritten =)

Answer 2

could you explain how you got that?

Answer 3

easy, I just wrote it twice =), you asked to REWRITE, so I wrote it once, and rewrote it again

Answer 4

Omg, lol.

Answer 5

what are you supposed to rewrite it as specifically?

Answer 6

Rewrite it in an algebraic expression in x

Answer 7

use the double formula :
sin2a = 2sinacosa

Answer 8

hmmmm shoot.. I didn't read it well... I see the issue now =)

Answer 9

I know but I don't know how to plug it in. It comes out to be like sqrt of 1-x^2 and i don't get how it comes out to be that way.

Answer 10

so, sin(2sin^-1x)
= 2sin(sin^-1 x) cos(sin^-1 x)

next, we knowed that the identity of :
cos^2 x = 1 - sin^2 x, then
cosx = sqrt( 1 - sin^2 x)

now we have :
2sin(sin^-1 x) cos(sin^-1 x)
= 2sin(sin^-1 x) sqrt(1 - (sin(sin^-1 x)^2))
= 2 x sqrt(1-x^2)

Answer 11

Thank you so much.

Answer 12

you're welcome