PLEASE HELP! MEDAL WILL DEFINIETLY BE GIVEN!!
Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

Question

PLEASE HELP! MEDAL WILL DEFINIETLY BE GIVEN!!
Express answer in exact form. 

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

anonymous · Answer

In problem 1 the smaller segment was-->$$A=(32/3 \pi - 16 sq rt 3) inches ^2$$

ranga · Answer

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ranga · Answer

Oh, then subtract the smaller segment area from the area of the entire circle to get the area of the larger segment.

anonymous · Answer

What's the area of the entire circle

ranga · Answer

Area of a circle = pi(r^2)
r = 8
Area = pi(8^2) = 64pi

anonymous · Answer

So the answer would be...

ranga · Answer

Area of the larger segment = Area of circle - Area of smaller segment
= 64pi - [ (32/3)(pi) - 16sqrt(3) ]

Just simplify the above.

anonymous · Answer

Ohhh otay :j

anonymous · Answer

Thank you soo much!!! If I needed some more help would you help me please?