I don't get this at all, can someone help me understand it?
I am not good at math, but can try. ASK!
So I'm given this image
And I'm having to complete this chart
I understand everything about and I'm usually alright at proofs, I just don't get which specific thing I would be proving with that
The last step says that PQ=RQ so that's what they want you to prove. Follow the steps in this geometric proof to see what the eight step is.
I did, and I just don't understand the prelude to it. Wouldn't that just be unecessary?
Does it have something to do with SQ equaling TQ?
@Hero
It is a prove that PQ=RQ.
Well yes, I think that's already been established
True. IDk, what exactly are you stuck on?
I have to figure out what statement 8 is, and I have no idea how to go about this. I tried to go through as a normal proof, and I still can't see it
Did they give you the shape that the proof/you is/are working on? It would be super difficult, if not impossible, for me to do it without the shape.
It was the first thing I posted. Here:
Everything alright Solomon?
lets follow the steps. in steps 1,2,3 the listed the givens. Step 1: ST=TQ saying that halves of ST are equal (that's 1 given) Step 2: ∠SQP=∠TQR saying that those 2 Q-angles that lay on ST, (without ∠PQR) are equal. Step 3: ∠RSQ=∠PTQ saying that those 2 sharp angles that are completely to the left, one toppest, and other is bottom-est are equal.
Uh huh
Read this, I explained everything thoroughly.
(Up to 4th step)
I did
So far so good?
@Luce, I can't go on, please say something.
OK, I'll assume you get it. If you don't go over it.
I did lol
READ CAREFULLY. Step 4: Find ∠SQR. this step implies that THE SUM OF two angles formed inside of the ∠SQR, (which are ∠SQP and ∠PQR) is equal to ∠SQR. ((( or ∠SQP+∠PQR = ∠SQR)))
Step 5: Says the same thing, as "step 4" but about ∠PQT. So far so good?
One sec
K
Yep I got that
Step 6: now we are saying that those big angles, SQR and TQP (those that look like about 140 degrees each) ARE EQUAL TO EACH OTHER> So far so good?
That's step 7 m8
Ok, so good, lets go on....
I'm here just in case you're wondering
Hint: Look at how ANGLE SQR and ANGLE PQR are proportional. (FIND THEM) We have proved that these two angles, (lets draw them)|dw:1384751171005:dw|
Hmm... that one other side is congruent?
Doesn't SQ equal QR as well? I'm so confused
No, which angle
QPT?
YES!!!!!!!!!!!!! and it has to be equal to?
SRQ?
Close, SRQ, the acute one.
how do you prove that?
Hint: if you have AA, you can imply AAA.
And I do have AA, but I thought that was only for similarity?
We are trying to prove they are proportional.
I understand why you are confused. basically, it should be, Step 8: knowing AAA and one side is equal therefore they are proportional. Step 9: Since we have ASA (or ASAA, which ever you like) we can imply that PQ=RQ
I still don't understand goddamn
Do you know how we have AA?
Because SQR=TQP and RSQ=PTQ
@SolomonZelman
@Mertsj
I am here.
You have ASA, right?
Yes because SQ=TQ
YES! This is the EIGHT step.
restate that these angles are congruent by ASA in the 8th step (and the proof implies that PQ=RQ in the 9th step)
So Triangles PQT and RQS are congruent by ASA?
Hullo?
@SolomonZelman
@Hero @Mertsj I just need to finish this
yes, they are congruent by ASA, so state that in your 8th step.
Thank you so much, can you help me with one last proof? How do I give you a medal?
Click best response, if you really think i deserved it.
You did. Can you help me with one more?
Maybe, but please make a separate question/thread for this.
Oh ok.
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