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Mathematics 17 Online
OpenStudy (anonymous):

I don't get this at all, can someone help me understand it?

OpenStudy (solomonzelman):

I am not good at math, but can try. ASK!

OpenStudy (anonymous):

So I'm given this image

OpenStudy (anonymous):

And I'm having to complete this chart

OpenStudy (anonymous):

I understand everything about and I'm usually alright at proofs, I just don't get which specific thing I would be proving with that

OpenStudy (solomonzelman):

The last step says that PQ=RQ so that's what they want you to prove. Follow the steps in this geometric proof to see what the eight step is.

OpenStudy (anonymous):

I did, and I just don't understand the prelude to it. Wouldn't that just be unecessary?

OpenStudy (anonymous):

Does it have something to do with SQ equaling TQ?

OpenStudy (anonymous):

@Hero

OpenStudy (solomonzelman):

It is a prove that PQ=RQ.

OpenStudy (anonymous):

Well yes, I think that's already been established

OpenStudy (solomonzelman):

True. IDk, what exactly are you stuck on?

OpenStudy (anonymous):

I have to figure out what statement 8 is, and I have no idea how to go about this. I tried to go through as a normal proof, and I still can't see it

OpenStudy (solomonzelman):

Did they give you the shape that the proof/you is/are working on? It would be super difficult, if not impossible, for me to do it without the shape.

OpenStudy (anonymous):

It was the first thing I posted. Here:

OpenStudy (anonymous):

Everything alright Solomon?

OpenStudy (solomonzelman):

lets follow the steps. in steps 1,2,3 the listed the givens. Step 1: ST=TQ saying that halves of ST are equal (that's 1 given) Step 2: ∠SQP=∠TQR saying that those 2 Q-angles that lay on ST, (without ∠PQR) are equal. Step 3: ∠RSQ=∠PTQ saying that those 2 sharp angles that are completely to the left, one toppest, and other is bottom-est are equal.

OpenStudy (anonymous):

Uh huh

OpenStudy (solomonzelman):

Read this, I explained everything thoroughly.

OpenStudy (solomonzelman):

(Up to 4th step)

OpenStudy (anonymous):

I did

OpenStudy (solomonzelman):

So far so good?

OpenStudy (solomonzelman):

@Luce, I can't go on, please say something.

OpenStudy (solomonzelman):

OK, I'll assume you get it. If you don't go over it.

OpenStudy (anonymous):

I did lol

OpenStudy (solomonzelman):

READ CAREFULLY. Step 4: Find ∠SQR. this step implies that THE SUM OF two angles formed inside of the ∠SQR, (which are ∠SQP and ∠PQR) is equal to ∠SQR. ((( or ∠SQP+∠PQR = ∠SQR)))

OpenStudy (solomonzelman):

Step 5: Says the same thing, as "step 4" but about ∠PQT. So far so good?

OpenStudy (anonymous):

One sec

OpenStudy (solomonzelman):

K

OpenStudy (anonymous):

Yep I got that

OpenStudy (solomonzelman):

Step 6: now we are saying that those big angles, SQR and TQP (those that look like about 140 degrees each) ARE EQUAL TO EACH OTHER> So far so good?

OpenStudy (anonymous):

That's step 7 m8

OpenStudy (solomonzelman):

Ok, so good, lets go on....

OpenStudy (anonymous):

I'm here just in case you're wondering

OpenStudy (solomonzelman):

Hint: Look at how ANGLE SQR and ANGLE PQR are proportional. (FIND THEM) We have proved that these two angles, (lets draw them)|dw:1384751171005:dw|

OpenStudy (anonymous):

Hmm... that one other side is congruent?

OpenStudy (anonymous):

Doesn't SQ equal QR as well? I'm so confused

OpenStudy (solomonzelman):

No, which angle

OpenStudy (anonymous):

QPT?

OpenStudy (solomonzelman):

YES!!!!!!!!!!!!! and it has to be equal to?

OpenStudy (anonymous):

SRQ?

OpenStudy (solomonzelman):

Close, SRQ, the acute one.

OpenStudy (solomonzelman):

how do you prove that?

OpenStudy (solomonzelman):

Hint: if you have AA, you can imply AAA.

OpenStudy (anonymous):

And I do have AA, but I thought that was only for similarity?

OpenStudy (solomonzelman):

We are trying to prove they are proportional.

OpenStudy (solomonzelman):

I understand why you are confused. basically, it should be, Step 8: knowing AAA and one side is equal therefore they are proportional. Step 9: Since we have ASA (or ASAA, which ever you like) we can imply that PQ=RQ

OpenStudy (anonymous):

I still don't understand goddamn

OpenStudy (solomonzelman):

Do you know how we have AA?

OpenStudy (anonymous):

Because SQR=TQP and RSQ=PTQ

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

@Mertsj

OpenStudy (solomonzelman):

I am here.

OpenStudy (solomonzelman):

You have ASA, right?

OpenStudy (anonymous):

Yes because SQ=TQ

OpenStudy (solomonzelman):

YES! This is the EIGHT step.

OpenStudy (solomonzelman):

restate that these angles are congruent by ASA in the 8th step (and the proof implies that PQ=RQ in the 9th step)

OpenStudy (anonymous):

So Triangles PQT and RQS are congruent by ASA?

OpenStudy (anonymous):

Hullo?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

@Hero @Mertsj I just need to finish this

OpenStudy (solomonzelman):

yes, they are congruent by ASA, so state that in your 8th step.

OpenStudy (anonymous):

Thank you so much, can you help me with one last proof? How do I give you a medal?

OpenStudy (solomonzelman):

Click best response, if you really think i deserved it.

OpenStudy (anonymous):

You did. Can you help me with one more?

OpenStudy (solomonzelman):

Maybe, but please make a separate question/thread for this.

OpenStudy (anonymous):

Oh ok.

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