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What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)? Show your work or explain the steps that you used to determine your answer.
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@Nurali
In order to go about this problem, you'll first need to find the moles of Mn in that amount of atoms. You can find the moles by dividing the amount of atoms by Avogadro's number, 6.02 x 10^23. [6.12 x 10^24 atoms] / [6.02 x 10^23 moles/atoms] = 10.2 moles Mn Next multiply the moles of Mn by its molar mass, 54.94. The molar mass of a substance the mass of 1 mole of that substance. 10.2 mol x 54.94 grams/mol = 558. grams So about 558 grams of Manganese.
@Nurali is this the answer
Yes
ok thank you soo much
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