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y = 3x^2 put each pair of x, y values and see which one satisfies the function.
yes. The first coordinate is x. The second coordinate is y.
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y = 3x^2 First choice is (1,3) put x = 1 and see if you get y = 3 y = 3x^2 x = 1 y = 3(1^2) = 3 So (1,3) satisfies the equation. That means (1,3) lies on the function h(x) = 3x^2
You should try each point in the answer. The last one also lies on the function.
No (1,9) would NOT work. y = 3x^2 put x = 1 and you get y = 3 * (1^2) = 3 * 1 = 3 which is NOT 9. So (1,9) does NOT lie on the function.
No, (-1, -3) will NOT work. y = 3x^2 put x = -1 y = 3 * (-1)^2 = 3 * 1 = 3 which is not -3. Therefore (-1,-3) does NOT lie on the function. Remember, (-1)^2 = (-1) * (-1) = +1
Yes. I was answering two other questions.... Yes, the first and the last points lie on the function.
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