Question

What is the vertex of the graph of y=-4(x+2)^2+5. Please help quickk!!!!!! I will give a medal for the right answer.

Answer 1

http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms.png should be very conspicuous, the equation is already in "vertex form"

Answer 2

the vertex form of such a graph is y = a(x-h)^2 + k
a = how much it is stretched/shrunk
and (h , k) = vertex

Answer 3

can u solve it ?

Answer 4

... there is nothing to be solved, just take numbers out of what was given to you
y=-4(x+2)^2+5
^ ^
y = a(x- h)^2+k
when vertex is (h, k)

Answer 5

here are the choices (2, 5)
(-2, 5)
(5, -2)
(5, 2)

Answer 6

Oh okay i understand.

Answer 7

but be careful that it is a Negative 2 comma 5 that you got...
many people tend that make that mistake :)

Answer 8

okay can you help with another Q

Answer 9

sure :)

Answer 10

solve (x+2)^2=1

Answer 11

foil
get all values to one side
then factor

Answer 12

can you show me how ?

Answer 13

okay, so do you know how to foil
(x + 2)^2 = ?

Answer 14

no

Answer 15

how about if it looked like this:
(x + 2)(x + 2) = ?

Answer 16

(x + 2)^2 = (x + 2)(x + 2) = x^2 + 4x + 4
so you get x^2 + 4x + 4 = 1
- 1 -1
x^2 + 4x + 3 = 0
then factor so (x + 3)(x + 1) = 0
so solve for x when
x + 3 = 0 and x + 1 = 0
that would give you your answers :)