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Mathematics 20 Online
OpenStudy (pixiedust1):

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OpenStudy (anonymous):

Distribute the x(A+B), so you should now have R= AX+BX Subtract the AX to the other side. The equation should now be R-AX=BX divide each term by X to get B

OpenStudy (pixiedust1):

So it would be B=(R-Ax)/x

OpenStudy (anonymous):

Well the Ax/x would cancel so it should be B= (R-A)/x

OpenStudy (pixiedust1):

Oh okay. My answer options are B=(R-A)/x B=(A-Rx)/x B=(R-Ax)/x

OpenStudy (anonymous):

The first one

OpenStudy (pixiedust1):

Thank you :)

OpenStudy (anonymous):

No problem! :)

Directrix (directrix):

@Anecia23 Why is the second option incorrect? B=(A-Rx)/x

OpenStudy (pixiedust1):

That's what I was wondering :) My answer to it was the second one too

Directrix (directrix):

I now think it is the third option. >> B=(R-Ax)/x Let's quickly rework the problem.

OpenStudy (pixiedust1):

Oops! Yeah, I agree with you. I just checked and it showed I came To the answer of B=(R-Ax)/x

Directrix (directrix):

R=x(A+B) R = xA + xB R - xA = xB R - xA = xB ------ ----- x x R - xA = B ------ x @PixieDust1 --> Is this the second or the third option?

OpenStudy (pixiedust1):

Third :)

Directrix (directrix):

That is what I got. B=(R-Ax)/x

OpenStudy (pixiedust1):

Wow!, that was very organized :D

Directrix (directrix):

That is the only way I know how to do these without mixing up the variables.

OpenStudy (pixiedust1):

Thank you for stepping up and helping me :) You saved me from getting one wrong!!

Directrix (directrix):

You are welcome.

OpenStudy (pixiedust1):

Have a great day/night

Directrix (directrix):

You, too.

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