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OpenStudy (anonymous):
Distribute the x(A+B), so you should now have R= AX+BX
Subtract the AX to the other side. The equation should now be R-AX=BX
divide each term by X to get B
OpenStudy (pixiedust1):
So it would be
B=(R-Ax)/x
OpenStudy (anonymous):
Well the Ax/x would cancel so it should be B= (R-A)/x
OpenStudy (pixiedust1):
Oh okay. My answer options are
B=(R-A)/x
B=(A-Rx)/x
B=(R-Ax)/x
OpenStudy (anonymous):
The first one
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OpenStudy (pixiedust1):
Thank you :)
OpenStudy (anonymous):
No problem! :)
Directrix (directrix):
@Anecia23 Why is the second option incorrect?
B=(A-Rx)/x
OpenStudy (pixiedust1):
That's what I was wondering :)
My answer to it was the second one too
Directrix (directrix):
I now think it is the third option. >> B=(R-Ax)/x
Let's quickly rework the problem.
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OpenStudy (pixiedust1):
Oops! Yeah, I agree with you. I just checked and it showed I came To the answer of
B=(R-Ax)/x
Directrix (directrix):
R=x(A+B)
R = xA + xB
R - xA = xB
R - xA = xB
------ -----
x x
R - xA = B
------
x
@PixieDust1 --> Is this the second or the third option?
OpenStudy (pixiedust1):
Third :)
Directrix (directrix):
That is what I got. B=(R-Ax)/x
OpenStudy (pixiedust1):
Wow!, that was very organized :D
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Directrix (directrix):
That is the only way I know how to do these without mixing up the variables.
OpenStudy (pixiedust1):
Thank you for stepping up and helping me :)
You saved me from getting one wrong!!