What is the magnetic filed strength? Any help is great! (: An electron is moving at 7.4x10^5 m/s perpendicular to a magnetic field. It experiences a force of -2.0x10^-13 N.

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anonymous · Answer

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anonymous · Answer

$$ \textbf F_B = q \textbf v \times \textbf B$$
$$ F_B = qvB \sin \theta$$
Theta is the angle between the velocity and the magnetic field - since the force and the velocity are perpendicular, the velocity and the magnetic field will also be perpendicular, so theta = 90º; sin 90º = 1

$$B=\frac{ F_B}{qv} $$

Also remember that the charge is negative, and the force is in the negative y direction, so the resultant magnetic force will be in the positive z direction (out of the page).

anonymous · Answer

Is 1.7 T correct? @AllTehMaffs

anonymous · Answer

@J.Velasquez  Yup yup ^_^   (sorry for the late response)

anonymous · Answer

It's okay >.< Thank you so much!

anonymous · Answer

Welcome ^_^