A = 41°, B =61°, c = 19 solve using the law of sines. round to the nearest tenth. please and thank you!

Question

johnweldon1993 · Answer

I thought we already solved this?

e.cociuba · Answer

Use the Law of Sines.

anonymous · Answer

@johnweldon1993 nooo, im still lost and never got the solution :/

e.cociuba · Answer

Hmm maybe @agent0smith can help. He's a good math teacher :)

agent0smith · Answer

|dw:1384823660224:dw|
$$\large \frac{ \sin A  }{ a } = \frac{ \sin B  }{ b } = \frac{ \sin C  }{ c } $$

anonymous · Answer

hello @agent0smith so i know that a/sin41 b/sin61 and c/sin19 and then sum of a triangles angles is 180 so angle 3 is 78. but where do i go from there?

agent0smith · Answer

Use the law of sines... |dw:1384823930955:dw|
plug in some numbers, pick a side to start with... i'll use C, c and A, a $$\large \frac{19  }{\sin 78 } = \frac{ a }{ \sin 41 }$$