Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (3psilon):

Determining convergence or divergence

OpenStudy (3psilon):

\[\sum_{n=1}^{n=\infty} \frac{ 2^n }{ n+1 }\]

OpenStudy (3psilon):

Please help

OpenStudy (anonymous):

The ratio test is your friend here. If \(a_n=\dfrac{2^n}{n+1}\), then the ratio test tells you that \(\sum a_n\) converges if the following is satisfied: \[\lim_{n\to\infty}\frac{a_{n+1}}{a_n}<1\] In this case, you have \[\lim_{n\to\infty}\frac{2^{n+1}}{n+1+1}\cdot\frac{n+1}{2^n}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!