Question

Help with integrals? Has to do with ln(x) and I'm having trouble with that

Answer 1

What is your question?

Answer 2

\[\frac{ 5 }{ x }-2e^x\]
and \[3x ^{-1}+3\]

Answer 3

i give you some hints

dy/dx(lnx) = 1/x

dy/dx(e^x) = e^x

x^(-1) = 1/x

try doing it now

Answer 4

Could \[\frac{ 5 }{ x }\] be written as \[5\ln(x)\]

Answer 5

yup the integral of 5/x is 5ln(x)

Answer 6

\[-2e^x\] would stay the same when integrated?

Answer 7

yup thats correct

Answer 8

I got that answer before but when I enter in the answer, it says that the domain doesn't match the correct answer?

Answer 9

i give show you how i would write the answer

\[\int\limits_{}^{}\ \frac{ 5 }{ x } - 2e^x = 5\ln(x) -2e^x + c \]

Answer 10

That's the answer I entered and it said the domain doesn't match and c is not defined in this context

Answer 11

that should be correct, unless this is a definite integral then i would need the intervals you are integrating over

would it be possible to see the complete problem? (take a pic and post it here)

Answer 12

try using log(x) instead of ln(x)

Answer 13

so 5log(x) - 2e^x + c

Answer 14

Still says the domain doesn't match...

Answer 15

theres something wrong with this.. it should be right the only other thing i can think of is

is f(x) is the function your integrating then F(x) is denoted to be an anti derivative of f(x)

Answer 16

so F(x) = 5log(x) - 2e^x + C

Answer 17

I can't really think of any other way to write it...

Answer 18

what math program is this? webassign?

can you possibly show me how you type the answer?

Answer 19

Some website called WeBWorK
I write it like: 5ln(x)-2e^x
(said to leave out C unless specified)

Answer 20

i really dont see what is wrong with this
everything should be correct, i suggest you notify the prof/teach/instructor about this

Answer 21

Hm, just got it. Apparently I was supposed to put x as an absolute value in ln so it would be ln(abs(x))

Answer 22

Thanks for trying to work it out with me ^^;

Answer 23

wow geez, they are so picky about the answer lol
well im glad it worked out okay, sorry i couldnt help much haha