Algebra II topic question:
Say I have a question that asks for a vertex and the axis of symmetry of an equation? How would I find it?
I have a homework question that is like:
$$y = –x^2 + 6x – 16$$ (This isn't the actually homework question just wondering how would I go about solving something like this?)
The textbook says:
To use this formula $y=a(x−h)^2+k$ with vertex of $(h,k)$ and axis of symmetry $x=h$.
I have only use $y=a(x−h)^2+k$ for vertical stretching... So I honestly don't have a clue on how to go about this.

Question

Algebra II topic question:
Say I have a question that asks for a vertex and the axis of symmetry of an equation? How would I find it?
I have a homework question that is like:
$$y = –x^2 + 6x – 16$$ (This isn't the actually homework question just wondering how would I go about solving something like this?)
The textbook says:
To use this formula $y=a(x−h)^2+k$ with vertex of $(h,k)$ and axis of symmetry $x=h$.
I have only use $y=a(x−h)^2+k$ for vertical stretching... So I honestly don't have a clue on how to go about this.

zale101 · Answer

they want you to turn the quadratic equation into the vertex formula

anonymous · Answer

Sorry if this sounds stupid but what's the vertex formula? 
Is it: $$y=a(x−h)^2+k$$

zale101 · Answer

yea it is that one
a indicates what position the parabola is at, upward or downard
h is the x, what side is the formula is positioned at right or left
and at last, k is y, if the parabola up or down

zale101 · Answer

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