Question

GIVING MEDALS
if a=22, b=14, and c=30, find the area of triangle ABC

Answer 1

HERON'S FORMULA OP :D
s=0.5(22+14+30)=33

Answer 2

Area
\[=\sqrt{s(s-a)(s-b)s-c)}\]
\[=\sqrt{33*11*19*3}\]

Answer 3

\[=33\sqrt{19}\]

Answer 4

is that the answer?!

Answer 5

yep

Answer 6

just checked with wolfram alpha, which agrees with me

Answer 7

You can use Heron's formula, which is:
sq rt [s(s-a)(s-b)(s-a)], where s = (a+b+c)/2

From there, you plug in your numbers.

s = (22+14+30)/2
s = 33

Then you plug s into Heron's formula.

= sq rt [s(s-a)(s-b)(s-a)]
= sq rt [33(33-22)(33-14)(33-30)]
= sq rt [33(11) (19) (3)]
= sq rt [20691]
= 143.84


The answer is D.

Answer 8

where is the choices given?

Answer 9

are*

Answer 10

its not multiple choice

Answer 11

well i said the answer is 33sqrt(19), which is approximately equivalent to 143.84