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Expand the logarithmic expression logb square root of 13/74 1. 1/2 logb 13 - 1/2logb 73 2. 1/2 logb 13 + 1/2logb 73 3. logb (13-73) 4. sqrt logb (13-73)
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\[\log_b(\sqrt{\frac{13}{17}})\]?
no 13/74
\[\log_b\left(\sqrt{\frac{13}{73}}\right)\] like that?
haha yes that's it
first rewrite the radical in exponential notation as \[\log_b\left({\frac{13}{73}}\right)^{\frac{1}{2}}\] then the \(\frac{1}{2}\) comes out front as \[\frac{1}{2}\log_b(\frac{13}{73})\]
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after that use \(\log(\frac{A}{B})=\log(A)-\log(B)\) to give you \[\frac{1}{2}\left(\log_b(13)-\log_b(73)\right)\]
and finally distribute the \(\frac{1}{2}\)
so, 1/2 logb 13- 1/2logb 73?
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