Question

Is there anyone out there that knows calculus I need help real bad??

Answer 1

haha yeah

Answer 2

Sorry didn't see your last response and closed out the question

Answer 3

So quotient rule
X^2/3 (x-5)

X^2/3
X-5^-1

Answer 4

oh ok so its
\[x^{2/3} (x-5)\]

Answer 5

Yes

Answer 6

misread it...no quotient rule needed then because there is no denominator

Answer 7

use product rule

Answer 8

Ok! So product

Answer 9

Simplifying
x + 2 = 3x + -1x2 + 5

Reorder the terms:
2 + x = 3x + -1x2 + 5

Reorder the terms:
2 + x = 5 + 3x + -1x2

Solving
2 + x = 5 + 3x + -1x2

Solving for variable 'x'.

Reorder the terms:
2 + -5 + x + -3x + x2 = 5 + 3x + -1x2 + -5 + -3x + x2

Combine like terms: 2 + -5 = -3
-3 + x + -3x + x2 = 5 + 3x + -1x2 + -5 + -3x + x2

Combine like terms: x + -3x = -2x
-3 + -2x + x2 = 5 + 3x + -1x2 + -5 + -3x + x2

Reorder the terms:
-3 + -2x + x2 = 5 + -5 + 3x + -3x + -1x2 + x2

Combine like terms: 5 + -5 = 0
-3 + -2x + x2 = 0 + 3x + -3x + -1x2 + x2
-3 + -2x + x2 = 3x + -3x + -1x2 + x2

Combine like terms: 3x + -3x = 0
-3 + -2x + x2 = 0 + -1x2 + x2
-3 + -2x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
-3 + -2x + x2 = 0

Factor a trinomial.
(-1 + -1x)(3 + -1x) = 0

Subproblem 1
Set the factor '(-1 + -1x)' equal to zero and attempt to solve:

Simplifying
-1 + -1x = 0

Solving
-1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1x = 0 + 1
-1x = 0 + 1

Combine like terms: 0 + 1 = 1
-1x = 1

Divide each side by '-1'.
x = -1

Simplifying
x = -1
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {-1, 3}
sorry it's long

Answer 10

f = x^2/3 ........ f' = ?
g = x-5 ..........g' = ?

Answer 11

holy crap !
did you mean to post that here?

Answer 12

yah

Answer 13

I'm so confused now??

Answer 14

I'm sorry angel12310 but I don't understand?? I'm taking first and second derivates and drawing graphs

Answer 15

why?

@angel12310 , can you delete post its not relevant to this thread

Answer 16

So dumb cow?

Answer 17

(fg)' = f'g + fg'

f = x^2/3 f' = ?
g = x-5 g' = ?

Answer 18

Do I put them together or or f(x) g'(x) + f'(x) g(x)

Answer 19

what do you mean "put together"? you wrote it right

Answer 20

Well what I meant was do u multiply the x^2/3 with the x then the 5 then do product or do u do x^2/3 which is f(x) then derivate of g'(x) which is 1 then add and take the derivate of f'(x) then g(x) ??

Answer 21

uh the 2nd thing you said

Answer 22

Ok lol!! I'm unsure of myself so I might ask crazy questions but I understanding u

Answer 23

So the f'(x)= (x^2/3)(1)+(2/3x^-1/3)(x-5)

Answer 24

looks good...now distribute the 2nd term because it will simplify further

Answer 25

Ok I'm stuck how will I do that? (2/3x^-1/3)(x) then (2/3x^-1/3)(-5)

Answer 26

yes

Answer 27

exponent rule
\[x^{m} x^{n} = x^{m+n}\]

Answer 28

So... 2/3x^(-1/3)+(x-5)

Answer 29

I'm not really sure what u mean!

Answer 30

\[x^{-1/3} * x = x^{-1/3 + 1} = x^{2/3}\]
\[\rightarrow x^{2/3} +\frac{2}{3}x^{2/3} -\frac{10}{3}x^{-1/3}\]

Answer 31

Oh ok! So then I set that equal to 0 and solve?

Answer 32

Or do I subtract 2/3x^1/3- 10/3x^-1/3

Answer 33

umm i guess, i thought we were just taking derivative

Answer 34

I have to take first derivate then get critical points find inc./dec. max/min. Then take second derivate find concave up/down inflection points then graph

Answer 35

oh wow we got a ways to go

Answer 36

Uuuggg yes

Answer 37

you need to review your algebra (simplifying combining exponents, etc...) otherwise these derivatives will take forever

Answer 38

We'll this is due in like 1hr

Answer 39

So can I do this
X^5/3 - 5x^2/3
5/3x^2/3-10/3x^-1/3
5/3x^1/3(x-2)=0

5/3x^-1/3=0 Then x-2=0

Answer 40

yes correct

Answer 41

So then x=0. X=2

Answer 42

R u still there?