find v w where v = 3i + j and w = i +3j
v 'cross' w ? v 'dot' w?
ARE THEY COMPLEX NUMBER? OR VECTORS?
i and j... i bet vectors...
I agree with you DemolisionWolf
@scooper04 please we'd like you to reply
sorry v dot x
v 'dot' w means you multiply the coefficients of the i componenets together and multiply the coefficients of the j components together. v = 3i + j w = i +3j v 'dot' w = (3)(1)i + (1)(3)j
The dot product of two vectors a and b is given by \[a_{x}b_{x}+a_{y}b_{y} +...+a_{n}b_{n}\]
so the answer 3i + 3j
Yes!
ok what do i do with this one. find u(vdotw) where u = 2i - j, v=3i+j and w=i+4j?
and you add the coefficients now. v 'dot' w = (3)(1)i + (1)(3)j = 3+3 = 6 a dot product will return a single value. where as a cross product will return a vector
u=2i - j, v=3i+j and w=i+4j u(vdotw) so do the dot product for vectors V and W first..
so the answer for the first one is 6? not 3i +3j?
ya
when you put this: u(vdotw) do you mean: u * (v 'dot' w) or u 'dot' (v 'dot' w)?
u(v dot/times w)
i'm not sure what to do with the u on this new question... I think the dot product of V and W will become a scalar that we just multiply the u vector by
ya, I was right in what I was thinking for the second question, just checked
so what does it look like im confused. im not good with this stuff and thursday is my last class.
first do the dot product for vector V and W because they are inside the ( )
that will give you a sinlgle number. multiply that number to each term in the u vector , and ur dun
so (3)(4)i * (4)(3)j ?
u=2i - j, v=3i+j and w=i+4j u(vdotw) = 2i - j (3*1 + 1*4)
I gotta take off, but do you see where the "3*1 + 1*4" comes from? the coefficients of the vectors V and W, take the i's times the i's coefficients, then the j's times the j's coefficients.
yeah i got ya
so it the answer 1
or 2 or neither
cool, so then u(vdotw) = 14i - 7j
sorry, open study crashed on me
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