Question

HELP WITH CALC! PROBLEM ATTACHED!

Answer 1

Let (x,y) be a point on the curve in the first quadrant.
y = (5-x) / (3+x)
The two sides of the rectangle formed with the x and y axes will be x and y.
Area A = xy

Find dA/dy. Set it to 0 and solve for x to find the one that will give the maximum area A.

Answer 2

@ranga, when you get a chance, i was able to attach the question. (no hurry at all, whenever you get the chance, just stop by)
:D

Answer 3

i did A' set it equal to 0 and got -3

Answer 4

well i did y' actually

Answer 5

I have not done the calculations myself. But if that is the procedure you followed then probably you are correct.

Answer 6

I am getting when x = 1.8989 it will have the maximum area.

Answer 7

y = (5-x) / (3+x)
A = xy
A = x(5-x) / (3+x) = (5x - x^2) / (3 + x)
To maximize the area, set dA/dx = 0 and solve for x.

Answer 8

x = 1.8990
Max area = 1.2021