Ambiguous Case 2nd Set Of Solutions (as seen in the picture within the next post) The 2nd set of answers should be: B = 107.79 degrees, C = 14.21 degrees, c = 3.30 The answers so far are: B = 72.21 degrees, C = 49.79 degrees, c = 10.27 Angle A was given to be at 58 degrees, a to be 11.4, and b to be 12.8
What was the question ?
The triangle has 2 sets of answers. How do you get the 2nd angle of C, B, and side c.
I got B prime as 180-angle B (180-72.21) degrees... = 107.79 degrees.
I got the previous answers using the law of sines, but I don't know how to get the other two remaining solutions (C prime, and the 2nd solution for side c). C prime should = 14.21 degrees, and the 2nd solution for side should equal 3.30
Assume the unknown side to be x and try the law of cosines. You will get a quadratic equation in x that will yield two sets of solutions.
I get the 1st side of c (10.266), or 10.27, as seen in my answer using law of sines.
The other solution should be c = 3.3
Yes, please show me how to get it if you can.
Starting from scratch, assume the unknown side to be x. Apply the law of cosines: x^2 + 12.8^2 - 2(12.8)(x)(cos(58) = 11.4^2 This will simplify to: x^2 - 13.57x + 33.8 = 0 Solve for x using quadratic formula and you will get x = 10.27 or 3.3 Then apply the law of sine to get one unknown angle. Use use the fact the angles of a triangle sum up to 180 degrees to get the third angle.
Never mind. :P
With so many angles and sides, I got mixed up with with which are the primes, and which are the first ones. 180-107.79-58=14.21 degrees.
thank you :)
you are welcome.
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