Question

LOGARITHM HELP NEEDED!!!

Answer 1

\[\log_{a} b=c\] and \[\log_{b} a=c-1\]
Write as a= something, using b in the something

Answer 2

oh wait that was supposed to say \[\log_{a} b ^{2}=c\]

Answer 3

log(a,b^2)=c; log(b,a)=c-1. subtract the two equations: log(a,b^2)-log(b,a)=1.
thus log(b^2)/log(a)-log(a)/log(b)=1.
let log(a)=x.
log(b^2)/x-x/log(b)=1.
-x^2/log(b)+log(b^2)=x
x^2/log(b)+x-log(b^2)=0
solve for x; a=e^x.
by log, i mean natural log.