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Mathematics 21 Online
OpenStudy (anonymous):

How many solutions (using only nonnegative integers) are there to the following equation? x1 + x2 + x3 + x4 + x5 = 31

OpenStudy (kc_kennylau):

You can view this question as putting 4 separators between 31 same objects.

OpenStudy (anonymous):

I did that and got 214 which is incorrect, what am I missing?

OpenStudy (kc_kennylau):

how did you get 214? :)

OpenStudy (anonymous):

I factorialed 5 then added each object

OpenStudy (kc_kennylau):

It should be \(((31,4))\) (or 31 multichoose 4)

OpenStudy (anonymous):

So 744?

OpenStudy (kc_kennylau):

nope :/

OpenStudy (kc_kennylau):

wait sorry

OpenStudy (anonymous):

how did you reach your answer then?

OpenStudy (kc_kennylau):

it's not \(((31,4))\)

OpenStudy (kc_kennylau):

it should be \(((33,4))\) since there are 33 spaces to put 4 separators. Let me illustrate this

OpenStudy (anonymous):

Okay

OpenStudy (kc_kennylau):

|dw:1384927155224:dw|

OpenStudy (anonymous):

So its 2592

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