How many molecules does 0.773 moles of Ca(OH)2 contain?

Question

anonymous · Answer

Molecules to moles is dividing by Avogadro's constant (6.02x10^23)

So this would be... 1.279 molecules of Ca(OH)2 if I understood the question correctly....

kc_kennylau · Answer

you forgot the exponent :)

kc_kennylau · Answer

how did you get 1.279? :o

anonymous · Answer

Aaaaah o_o Correction.... 1.284 Molecules... becuase it's

0.773 / (6,02x10^23) = 1.284

anonymous · Answer

1.284x10^-24

aka 1.284 mol

kc_kennylau · Answer

I think a mole has many molecules? (?) :o

kc_kennylau · Answer

i would do $0.773\times6.02\times10^{23}=4.65346\times10^{23}$ molecules.

anonymous · Answer

But you're not following the rule of BODMAS.

Brackets
Operators
Multiplication
Addition
Subtraction

Therefore it's xing the 0.773 and the 6.02 first

anonymous · Answer

Oh gosh I think you're right though... we're doing moles to molecules! :O
Sorry!

anonymous · Answer

I read the question wrong!

anonymous · Answer

So, it would be yes, as you say 0.773 x (6.02x10^23)

anonymous · Answer

= 4.653 x10^23

kc_kennylau · Answer

oh thank you :)