Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

WHO IS REALLY SMART WITH MATH AND CAN HELP ME NOW PLZ?

OpenStudy (anonymous):

what do you want

OpenStudy (anonymous):

In the equation y = 1/4x + 8, what is y when x is 20?

OpenStudy (anonymous):

THESE ARE THE CHOICES: 28, 13, 12, 7

OpenStudy (anonymous):

HELLO?

OpenStudy (anonymous):

In the equation y = 1/4x + 8, what is y when x is 20? THESE ARE THE CHOICES: 28, 13, 12, 7

OpenStudy (unklerhaukus):

hi, substitute x=20 into your equation and simplify

OpenStudy (anonymous):

BUT HOW I DONT GET IT

OpenStudy (unklerhaukus):

y = 1/4*x + 8 x=20 y = 1/4*20 + 8

OpenStudy (anonymous):

so i have to multiply?

OpenStudy (unklerhaukus):

yes multiply 1/4 with 20 , then add 8

OpenStudy (anonymous):

ok wait plz

OpenStudy (anonymous):

I got 13, is that the right answer?

OpenStudy (anonymous):

@UnkleRhaukus is 13 the right answer?

OpenStudy (unklerhaukus):

what did you get for the first bit (just the multiplication)

OpenStudy (anonymous):

um... 5/1

OpenStudy (unklerhaukus):

Yes, good then your RIGHT ! 13 is correct

OpenStudy (anonymous):

yes thank you so much, can yo help me with one more question?

OpenStudy (unklerhaukus):

sure

OpenStudy (anonymous):

ok wait..

OpenStudy (anonymous):

Which of the following equations is graphed as a straight line? y = 3x y = 4/x y = 7x and the small 2 at the top xy = 8

OpenStudy (unklerhaukus):

Do have you drawn a parabola, or a hyperbola before?

OpenStudy (anonymous):

no the question just came like that...

OpenStudy (anonymous):

what hello?

OpenStudy (anonymous):

plz help me

OpenStudy (anonymous):

Which of the following equations is graphed as a straight line? y = 3x y = 4/x y = 7x and the small 2 at the top xy = 8

OpenStudy (aggie12341):

first one y=3x

OpenStudy (anonymous):

i will give a medal but plz help me

OpenStudy (aggie12341):

Give me a medal!

OpenStudy (anonymous):

ok wait

OpenStudy (aggie12341):

Add me as your friend and private message me. I'll help you privately.

OpenStudy (unklerhaukus):

a general form a a straight line is y=ax+b where 'a' and 'b' are numbers

OpenStudy (anonymous):

there

OpenStudy (anonymous):

ok wait

OpenStudy (aggie12341):

ok ttys

OpenStudy (anonymous):

@UnkleRhaukus is that the right answer y = 3x?

OpenStudy (unklerhaukus):

if there is a ' ^2 ' ie a small 2 at the top , then its a parabola (a curvy line) y=ax^2+bx+c where 'a' 'b' and 'c' are numbers

OpenStudy (anonymous):

so then which answer is it? cuz i dont get it

OpenStudy (unklerhaukus):

some form of a hyperbola are y=k/x yx=k where 'k' is a number a hyperbola is another type of curve(s)

OpenStudy (anonymous):

so it is the first answer?

OpenStudy (anonymous):

Which of the following equations is graphed as a straight line? y = 3x y = 4/x y = 7x and the small 2 at the top xy = 8

OpenStudy (unklerhaukus):

a general form a a straight line is y=ax+b where 'a' and 'b' are numbers in the option you think is correct , what numbers are 'a' and 'b' ?

OpenStudy (anonymous):

i dont know i am confuse plz help

OpenStudy (anonymous):

Which of the following equations is graphed as a straight line? y = 3x y = 4/x y = 7x and the small 2 at the top xy = 8

OpenStudy (anonymous):

i will give a medal just plz help

OpenStudy (unklerhaukus):

in the option you think is correct , what numbers are 'a' and 'b' ?

OpenStudy (phi):

Uncle is telling you the answer. the equation of a line looks like this: y = ax + b that means "a" number in front of a plain x plus another number "b" (which could be zero) if we let a= 3 and b=0 we get y = 3x + 0 or simply y= 3x that is the equation of a line

OpenStudy (anonymous):

oh ok thank you now i get it

OpenStudy (phi):

if you get it, then is this a line: y = 4x +2 ?

OpenStudy (anonymous):

ok bye thanks

OpenStudy (aggie12341):

13

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!