Question

What is the general form of the equation of the line shown?




x + y = 0
x - y = 0
-x - y = 0

Answer 1

what's its slope?

Answer 2

wat u see if wat i got so idk

Answer 3

do you know how to get the slope of a line?

Answer 4

no...

Answer 5

well... looking at the line we can pick 2 points from it... say
(0, 0) and (2, 2)

so we can use that to get the slope, so \(\bf\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&0)\quad &(2\quad ,&2)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\)

Answer 6

okay?

Answer 7

what would you get for the slope?

Answer 8

2?

Answer 9

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&0)\quad &(2\quad ,&2)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{2-0}{2-0}=1\)

Answer 10

idk math is my worst subject

Answer 11

so now that we know the slope of the line... we use that in the "point-slope form", so \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&0)\quad &(2\quad ,&2)
\end{array}
\\\quad \\

slope = m= 1
\\ \quad \\

y-y_1=m(x-x_1)\implies y-(0)=1(x-(0))\)

now just solve for "0" and that'd be the equation

Answer 12

??

Answer 13

I assume you've covered the slopes section already, otherwise this exercise wouldn't apply if you haven't

Answer 14

does anyone just know the answer

Answer 15

pick a point on the line...(3,3)
slope(m) = 1
y - y1 = m (x - x1)
y - 3 = 1(x - 3)
y - 3 = x - 3
y = x - 3 + 3
y = x + 0
-x + y = 0

are all the answer choices listed ?

Answer 16

yes they r

Answer 17

I am sorry....I do not know then :(

Answer 18

wait...I think I found it..
-x + y = 0 (multiply by -1 to make x positive)
x - y = 0

Answer 19

thanx ^.^

Answer 20

no problem :)