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Mathematics 14 Online
OpenStudy (precal):

I need help on a limit problem limit as x approaches -2 (x-2)/(x^2+4x+4)

OpenStudy (austinl):

If you plug it in directly what do you get?

OpenStudy (precal):

-4/0 DNE correct

OpenStudy (austinl):

That is what I get on first inspection. Have you learned L'Hospital's Rule?

OpenStudy (anonymous):

Yeah, you may want to look that rule up. I could tell what it approaching right now, but Its simple if you use the rule.

OpenStudy (precal):

yes

OpenStudy (precal):

ok so it is -1/4

OpenStudy (austinl):

I am getting \(-\infty\)

OpenStudy (precal):

no it still produces 1/0 DNE

OpenStudy (anonymous):

I got the same as austin

OpenStudy (precal):

how?

OpenStudy (anonymous):

It not where it lies on -2, but what direction it was heading.

OpenStudy (anonymous):

If you plug in other numbers near it, it keeps heading to infinity.

OpenStudy (anonymous):

*negative infinity

OpenStudy (shamil98):

(x-2)/(x^2+4x+4) using L'hopitals rule f'(x)/g'(x) 1/2x+4 1/2(-2) + 4 1/0 i got the same as precal o.o

OpenStudy (shamil98):

oh, that makes sense.

OpenStudy (anonymous):

x @ -2 is a zero

OpenStudy (anonymous):

*Hole, excuse me

OpenStudy (precal):

Yes, I should have looked at the graph...... Thanks

OpenStudy (anonymous):

No problem. Props to Austin as well.

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