Mathematics
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OpenStudy (precal):
I need help on a limit problem
limit as x approaches -2
(x-2)/(x^2+4x+4)
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OpenStudy (austinl):
If you plug it in directly what do you get?
OpenStudy (precal):
-4/0 DNE correct
OpenStudy (austinl):
That is what I get on first inspection. Have you learned L'Hospital's Rule?
OpenStudy (anonymous):
Yeah, you may want to look that rule up. I could tell what it approaching right now, but Its simple if you use the rule.
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OpenStudy (precal):
yes
OpenStudy (precal):
ok so it is -1/4
OpenStudy (austinl):
I am getting \(-\infty\)
OpenStudy (precal):
no it still produces 1/0 DNE
OpenStudy (anonymous):
I got the same as austin
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OpenStudy (precal):
how?
OpenStudy (anonymous):
It not where it lies on -2, but what direction it was heading.
OpenStudy (anonymous):
If you plug in other numbers near it, it keeps heading to infinity.
OpenStudy (anonymous):
*negative infinity
OpenStudy (shamil98):
(x-2)/(x^2+4x+4)
using L'hopitals rule
f'(x)/g'(x)
1/2x+4
1/2(-2) + 4
1/0
i got the same as precal o.o
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OpenStudy (shamil98):
oh, that makes sense.
OpenStudy (anonymous):
x @ -2 is a zero
OpenStudy (anonymous):
*Hole, excuse me
OpenStudy (precal):
Yes, I should have looked at the graph...... Thanks
OpenStudy (anonymous):
No problem. Props to Austin as well.