I know that the angle of a vector is 62 degrees and it has a longitude of 310. Which are the components?
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OpenStudy (kc_kennylau):
Sine rule: \(\dfrac{\sin a}a=\dfrac{\sin b}b=\dfrac{\sin c}c\)
OpenStudy (kc_kennylau):
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Is that what you mean
OpenStudy (osanseviero):
Yep
OpenStudy (osanseviero):
No
OpenStudy (osanseviero):
The 310 is the vector module (I dont know if you call it like that in English)
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OpenStudy (kc_kennylau):
what's your native language and you can draw that out
OpenStudy (kc_kennylau):
what is your native language
OpenStudy (osanseviero):
Spanish
OpenStudy (kc_kennylau):
Me puedes hablar en espanol porque lo comprendo
OpenStudy (kc_kennylau):
sos de argentina o eres de espana?
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OpenStudy (osanseviero):
I dont have any draw. The question says.
Write the vector in the form of its components. The angles that forms the vector with the positive part of the x-axis is 62, the module is 310
OpenStudy (osanseviero):
Ninguno
OpenStudy (kc_kennylau):
de donde eres/sos?
OpenStudy (osanseviero):
I don't know if you call it size or magnitude or module or longitude or how in english...mexico
OpenStudy (osanseviero):
So...what should I do next?
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OpenStudy (osanseviero):
I need to go, I will come back later, sorry
OpenStudy (kc_kennylau):
puedes dbujar lo que siginificas tu?
OpenStudy (osanseviero):
What I am saying is this
OpenStudy (osanseviero):
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OpenStudy (osanseviero):
|dw:1385004049057:dw|
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OpenStudy (kc_kennylau):
hi i'm back
OpenStudy (kc_kennylau):
lo puedes llamar "the long side of the right triangle" jaja
OpenStudy (kc_kennylau):
K uses teorema del seno \(\dfrac{sena}a=\dfrac{senb}b=\dfrac{senc}c\)
OpenStudy (kc_kennylau):
disculpe deberia estar \(senA\) en lugar de \(sena\)