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Mathematics 23 Online
OpenStudy (osanseviero):

I know that the angle of a vector is 62 degrees and it has a longitude of 310. Which are the components?

OpenStudy (kc_kennylau):

Sine rule: \(\dfrac{\sin a}a=\dfrac{\sin b}b=\dfrac{\sin c}c\)

OpenStudy (kc_kennylau):

|dw:1385001672837:dw| Is that what you mean

OpenStudy (osanseviero):

Yep

OpenStudy (osanseviero):

No

OpenStudy (osanseviero):

The 310 is the vector module (I dont know if you call it like that in English)

OpenStudy (kc_kennylau):

what's your native language and you can draw that out

OpenStudy (kc_kennylau):

what is your native language

OpenStudy (osanseviero):

Spanish

OpenStudy (kc_kennylau):

Me puedes hablar en espanol porque lo comprendo

OpenStudy (kc_kennylau):

sos de argentina o eres de espana?

OpenStudy (osanseviero):

I dont have any draw. The question says. Write the vector in the form of its components. The angles that forms the vector with the positive part of the x-axis is 62, the module is 310

OpenStudy (osanseviero):

Ninguno

OpenStudy (kc_kennylau):

de donde eres/sos?

OpenStudy (osanseviero):

I don't know if you call it size or magnitude or module or longitude or how in english...mexico

OpenStudy (osanseviero):

So...what should I do next?

OpenStudy (osanseviero):

I need to go, I will come back later, sorry

OpenStudy (kc_kennylau):

puedes dbujar lo que siginificas tu?

OpenStudy (osanseviero):

What I am saying is this

OpenStudy (osanseviero):

|dw:1385003977624:dw|

OpenStudy (osanseviero):

|dw:1385004049057:dw|

OpenStudy (kc_kennylau):

hi i'm back

OpenStudy (kc_kennylau):

lo puedes llamar "the long side of the right triangle" jaja

OpenStudy (kc_kennylau):

K uses teorema del seno \(\dfrac{sena}a=\dfrac{senb}b=\dfrac{senc}c\)

OpenStudy (kc_kennylau):

disculpe deberia estar \(senA\) en lugar de \(sena\)

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