How do you factor polynomials with cubic powers and polynomials with powers higher than cubic? help please.

Question

kc_kennylau · Answer

the simple answer is "no you don't"

kc_kennylau · Answer

the more complicated answer is you can try factors by the factor theorem

kc_kennylau · Answer

and the factors are often related to the constant term, e.g. the constant term is 9 and the factor can be x-9 or x-3 or x-1 or x-1/3 or x-1/9 or x+9 or x+3 or x+1 or x+1/3 or x+1/9 etc

kc_kennylau · Answer

If he says that the factors are integral you can try x=+-1 or x=+-2 or x=+-3 and don't forget x=0

kc_kennylau · Answer

in short, don't mess up with 'em

hope i helped you :)

anonymous · Answer

i wish it did but i have to know how to use them with synthetic division  on my algebra two quiz and i know how but the whole p and q rules that go with it are kind of confusion

kc_kennylau · Answer

do you have an example? :)

anonymous · Answer

3x^4- 75x^2  or 1-27x^6 either or will help just fine

kc_kennylau · Answer

oh only two terms

kc_kennylau · Answer

$$3x^4-75x^2$$$$=x^2(3x^2-75)$$$$=3x^2(x^2-25)$$$$=3x^2(x+5)(x-5)$$
$$1-27x^6$$$$=(1-3x)(1+3x+9x^2)$$

anonymous · Answer

thank you so much

kc_kennylau · Answer

no problem :) just memorize the 5 identities by heart :)

kc_kennylau · Answer

1 and 2 $(x\pm y)^2=x^2\pm2xy+y^2$
3 and 4 $x^3\pm y^3=(x\pm y)(x^2\mp xy+y^2)$
5 $x^2-y^2=(x+y)(x-y)$