Question

closed

Answer 1

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

a = 2, b = 6, & c = -5

\[x = \frac{ -6\pm \sqrt{36+40} }{ 4 }\]

\[x = \frac{ -6\pm \sqrt{76} }{ 4 }\]

x = 0.7 or -3.7

Answer 2

Given 2x^2 + 6x - 5 = 0
we have ax^2+bx+c=0
here a=2
b=6
and c=-5
then x= [-b±√(b^2-4ac)]/(2a)
=>x=[-6±√(6^2-4*2*-5)]/(2*2)
=>x=[-6±√(36+40)]/4
=>x=[-6±√76]/4
then x=0.67
and x=-3.67

Know more about Quadratic Curve http://goo.gl/BJxcSp