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Mathematics 12 Online
OpenStudy (gschibby):

Can someone explain how this is possible? :P

OpenStudy (gschibby):

OpenStudy (lncognlto):

The differentiation of xy = xy' + y, when differentiated according to the product rule... But beyond this, I'm not sure.

OpenStudy (gschibby):

Hm, ok. I guess I have more reading to do :P

OpenStudy (lncognlto):

xD Sorry I can't help more...

OpenStudy (gschibby):

Annoying when you feel like you HAVE to understand it :P

OpenStudy (cwrw238):

this is a differential equation and as incognito says it is using the product rule in reverse the next step to solve the equation would be to integrate both sides

OpenStudy (cwrw238):

this will give you the general solution which is an equation relating y and x and including the constant of integration

OpenStudy (cwrw238):

does this help?

OpenStudy (gschibby):

Yup!^^ Thanks!

OpenStudy (unklerhaukus):

\[\frac{d}{dx}(yx)=\frac{dy}{dx}x+y\frac{dx}{dx}\\\qquad\qquad=y'x+y\]

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