Question

log base 5(3x+2)+log base 5(x-1)=1

Answer 1

apply first laws of log at left side of the equation.... that is....\[\log_{5}m + \log_{5}n = \log_{5}mn \]

Answer 2

then raise both side by 5... that will simplify the expression and you can solve for x....

Answer 3

can you make it?

Answer 4

\[5^{\log_{5}x }=x\]

Answer 5

... 5 raise to log base 5 of x is simply equal to x... is just a sample you can reference to given equation above....

Answer 6

sooo i got log base 5 (3x^2-x-2)=1 ....what do i do next??

Answer 7

no you applied it wrong.... 5 ^ log base 5 will cancel to 1...

Answer 8

to the right side... it would be 5^1 = 5

Answer 9

so the equation will become...
\[(3x+2)(x-1)=5\]

Answer 10

you can now simply solve for x....